Kiwongygcch

Representa la parábola y = –x2;P/2 = 3/4 y que se trata de una parábola que abre hacia arriba (pues el término cuadrático es x y no aparece un signo negativo) Por lo tanto Foco F(3, 2/33/4) F(3, 17/12) Directriz y = 2/3 – 3/4 y = 1/12 Con estos elementos podrás hacer un bosquejo de la gráfica fácilmente Espero la solución te sea útil, ¡saludos!A partir de ella, representa la parábola y = –(x 3)2 Halla el eje de simetría y las coordenadas del vértice,e indica si éste es un máximo o un mínimo Representa la parábola y = x 2; Using Properties Of Parabolas To Graph A Parabola Algebra And Geometry Help Y=1/2x^2 parabola

Step1 The first step is to multiply or divide both the linear equations with a nonzero number to get a common coefficient of any one of the variables in both equations Step2 Add or subtract both the equations such that the same terms will get eliminated5x = 2 y 7 (ii) 6x 7 y − 11 = 0 ;Solve by Addition/Elimination x2y=3 2x3y=9 Multiply each equation by the value that makes the coefficients of opposite Simplify Tap for more steps Simplify Tap for more steps Apply the distributive property Multiply by Multiply by Add the two Ncert Solutions For Class 10 Maths Chapter 3 Pair Of Linear Equations In Two Variables 3/x-1/y=-9 2/x 3/y=5 by elimination method